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-5x^2-2=14x
We move all terms to the left:
-5x^2-2-(14x)=0
a = -5; b = -14; c = -2;
Δ = b2-4ac
Δ = -142-4·(-5)·(-2)
Δ = 156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{156}=\sqrt{4*39}=\sqrt{4}*\sqrt{39}=2\sqrt{39}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{39}}{2*-5}=\frac{14-2\sqrt{39}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{39}}{2*-5}=\frac{14+2\sqrt{39}}{-10} $
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